(2y+3)(4y^2-5y-7)=

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Solution for (2y+3)(4y^2-5y-7)= equation: 


Simplifying
(2y + 3)(4y2 + -5y + -7) = 0

Reorder the terms:
(3 + 2y)(4y2 + -5y + -7) = 0

Reorder the terms:
(3 + 2y)(-7 + -5y + 4y2) = 0

Multiply (3 + 2y) * (-7 + -5y + 4y2)
(3(-7 + -5y + 4y2) + 2y * (-7 + -5y + 4y2)) = 0
((-7 * 3 + -5y * 3 + 4y2 * 3) + 2y * (-7 + -5y + 4y2)) = 0
((-21 + -15y + 12y2) + 2y * (-7 + -5y + 4y2)) = 0
(-21 + -15y + 12y2 + (-7 * 2y + -5y * 2y + 4y2 * 2y)) = 0
(-21 + -15y + 12y2 + (-14y + -10y2 + 8y3)) = 0

Reorder the terms:
(-21 + -15y + -14y + 12y2 + -10y2 + 8y3) = 0

Combine like terms: -15y + -14y = -29y
(-21 + -29y + 12y2 + -10y2 + 8y3) = 0

Combine like terms: 12y2 + -10y2 = 2y2
(-21 + -29y + 2y2 + 8y3) = 0

Solving
-21 + -29y + 2y2 + 8y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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